The value of C5 is selected/adjusted to achieve nominally zero tilt.Compensation isn't perfect due to the voltage dependence of the emitter base capacitance but the tilt can be significantly reduced,
Using transistors with lower emitter base capacitances also helps as does reducing the value of the output collector load resistor.
This requires increasing the tail current to maintain the output swing. The attached circuit produces a 3.3V pp output signal.For lower amplitude input signals capacitively coupling the emitters of the differential amplifier and splitting the current source so that each transistor has its own current source can be useful in minimising the effects of Vbe mismatches between the transistors.
Bruce Charles P. Steinmetz wrote:
James wrote:I'm trying to square the 10Mhz output from a Thunderbolt GPSDO, and failingmiserably. I'm still very new at this so please forgive my ignorance. I thought it was going to be easy. I have tried diodes, comparators, op-amps, Schmidt trigger buffers,regular buffers, inverters, anddifferential amplifier circuits. I must be missing something simple becausei just can't shape the wave into a square wave. Has any one done this?I concur with Bruce that most of these should work. More details about what you have tried (i.e., schematics), and what results you have gotten, will be necessary for us to be able to help you. (The list accepts small attachments.)Meanwhile, here are two links you can peruse that give several shaping circuits (the second link is Bruce's work):http://www.wenzel.com/documents/waveform.html http://www.ko4bb.com/dokuwiki/doku.php?id=precision_timing:clock_shapers Best regards, Charles _______________________________________________ time-nuts mailing list -- time-nuts@febo.comTo unsubscribe, go to https://www.febo.com/cgi-bin/mailman/listinfo/time-nutsand follow the instructions there.
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