Hi If your 10 MHz is the result of a “divide by 2 then divide by 5” approach, the output will not be a 50/50 duty cycle square wave. The best way to fix that is to move up the chain and play with the dividers. You need to re-aragne them so the final divider is a divide by 2.
When you do so, consider that the final divider may be running a hundred ma of supply current rather than 10 or 20 ma. The shunt capacitor on that filter *does* make a difference. Bob > On Jul 24, 2015, at 4:30 PM, skipp Isaham via time-nuts <time-nuts@febo.com> > wrote: > > Hello again, > > First off, I want to thank everyone who replied direct and through the group > regarding my recent 10 MHz square to sine wave conversion info request. > > I obtained a mini-circuits 10.7 MHz low pass filter from Ebay cheap > enough and I also plan on "rolling my own" based on some of the information > and links provided in your generous replies. > > Part 2: > > With things in place, I actually looked at the actual square wave output port > with > a decent scope to see it's not even close to being symmetrical. The waveform > on-portion (duty cycle) appears (surprising to me) to be much less than 20% > > Now I'm under the assumption that proper rounding or conversion of the non > symmetrical 10 MHz square to a sine wave will be a bit more involved. > > Before I launch toward part two of this latest saga, I'd really be interested > in reading > suggestions and comments regarding methods to improve/fix the 10 MHz waveform > symmetry. > > Again, thank you in advance for your replies... > > Regards, > > skipp > skipp...@yahoo.com > > > _______________________________________________ > time-nuts mailing list -- time-nuts@febo.com > To unsubscribe, go to https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts > and follow the instructions there. _______________________________________________ time-nuts mailing list -- time-nuts@febo.com To unsubscribe, go to https://www.febo.com/cgi-bin/mailman/listinfo/time-nuts and follow the instructions there.