Hi John,
I hadn't run into this idea before, and I like it. But I have a problem with
the statement:. "If you move through space at 100,000,000 meters per second in
space, then your velocity in the t direction is 283,000,000 meters per second
(because sqrt(100E6^2 + 283E6^2) = 300E6.)" The problem is that your velocity
in the t direction remains the same to yourself, because your velocity as
compared to yourself is always zero. So, yes, velocity with respect to some
other object does change the rate of time as compared to that other object.
But, as is understood from reading your whole post, time is always moving at
the same rate for the one observing himself.
Bob
From: John Miles <j...@miles.io>
To: 'Discussion of precise time and frequency measurement'
<time-nuts@febo.com>
Sent: Friday, November 27, 2015 2:54 PM
Subject: Re: [time-nuts] Einstein Special on PBS
So, here's how I finally grokked this stuff. c, the speed of light in a
vacuum, is often spoken of as a "speed limit" that nothing can ever exceed.
That's a bad way to put it, and people who have expressed it that way in
popular science writing for 100 years should feel bad.
Instead, the way to visualize relativity is to realize that c is the *only*
speed at which anything can travel. You are always moving at 300,000,000
meters per second, whether you want to or not. But you're doing it through all
four dimensions including time. If you choose to remain stationary in (x,y,z),
then all of your velocity is in the t direction. If you move through space at
100,000,000 meters per second in space, then your velocity in the t direction
is 283,000,000 meters per second (because sqrt(100E6^2 + 283E6^2) = 300E6.)
It doesn't make sense to speak of moving a certain number of "meters" through
time, so your location in time itself is what has to change. You won't
perceive any drift in your personal timebase when you move in space, any more
than you will perceive a change in your location relative to yourself. ("No
matter where you go, there you are.") But an independent observer will see a
person who's moving at 100,000,000 meters per second in x,y,z and 283,000,000
meters per second in t. They see you moving in space, in the form of a
location change, and they also see you moving in time, in the form of a
disagreement between their perception of elapsed time and your own.
Likewise, if you spend all of your velocity allowance in (x,y,z), your t
component is necessarily zero. Among other inconvenient effects that occur at
dt/dt=0, you won't get any closer to your destination, even though your own
watch is still ticking normally. Particles moving near c experience this
effect from their point of view, even while we watch them smash into their
targets at unimaginable speeds.
This is special relativity in action. The insight behind general relativity is
twofold: 1) movement caused by the acceleration of gravity is
indistinguishable from movement caused by anything else; and 2) you don't even
have to move, just feel the acceleration. That second part was what really
baked peoples' noodles. It is what's responsible for the disagreement between
the two 5071As.
-- john, KE5FX
Miles Design LLC
> Hi Mike,
>
> The time rate does remain the same - at the device. The problem is the idea
> that it is the hyperfine transitions that determine the time...
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