On 4/14/17 8:37 AM, jimlux wrote:
If one is counting an unknown 1pps source with a counter that runs at 10
MHz (e.g. the error in any one measurement is uniformly distributed over
1 ppm) and you collect 100 samples,
is the (1 sigma) measurement uncertainty 0.1ppm * sqrt(100)/sqrt(12)
(standard deviation of a uniform distribution is 1/sqrt(12) )
(assuming for the moment that both sources have no underlying
variability - we're talking about the *measurement uncertainty*)
Oops..
0.1 ppm * 1/sqrt(N) * 1/sqrt(12)
That is, the standard deviation goes down as sqrt(N)
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