Hi Bob,
I'm seeing 4.22E-12 as the slope value in the upper right of the TimeLab
phase difference plot. Is that telling me that my DUT is within +4.22ps
/ sec from my reference 1PPS for the 24 hour measurement duration?
I have attached a screen capture that will hopefully make its way
through for viewing.
Thanks,
Chris
On 07/02/19 11:50:10, Bob kb8tq wrote:
Hi
The difference in seconds between the start phase and the end phase divided by
the number
of seconds duration gives you the parts in whatever of the error.
If you see 1us ( = 1x10^-6 seconds) of change in a second, you are off by 1
ppm (or 1x10^-6).
If you see 1 us of change in 1,000 seconds you are off by 1 ppb (or 1x10^-9).
At a bit over 10
days (1,000,000 seconds) your 1 us change is 1 ppt (or 1x10^-12).
Bob
On Jul 2, 2019, at 10:17 AM, Chris Burford<cburfo...@austin.rr.com> wrote:
Is the slope value for the phase difference shown in TimeLab an average of the
overall data sample duration? The reason I ask is that my service manual for my
RFS says:
/"//A faster way to make the comparison between the reference frequency and the DUT
is to use the time interval measurement mode of the counters. In this case, the time
intervals between the 10MHz zero crossings of the reference frequency and the DUT are
measured and averaged. If this time interval changes by less than 10ps per second, then
the DUT is within 1 part in //10^11 of the frequency reference."/
I'm just curious if the phase difference slope value can be plugged in to this
equation.
Regards,
Chris
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