On 2021-02-11 13:49:48 +0100, Christian Jullien wrote:
> No, I think he probably meant (1F-1F) to get 0.0F value?

In the other function, f1 is a variable. I don't see why (1F-1F)
would be used: 0.0F would be simpler, and even that, there should
be no difference with 0.0, because the zero is converted to
long double (and this is why Ayush complained). Still, I don't
see the reason of the change.

-- 
Vincent Lefèvre <vinc...@vinc17.net> - Web: <https://www.vinc17.net/>
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Work: CR INRIA - computer arithmetic / AriC project (LIP, ENS-Lyon)

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