My Apache 2.0.49  Tomcat 5.0.19, windows 2000.
I have a difficult in running servlet from Apache.
For example I have a servlet TestServlet.class (package: myServlet) in
C:\Program Files\Apache
Group\Apache2\tomcat\webapps\ROOT\WEB-INF\classes\myServlet\
I register this servlet in  \tomcat\webapps\ROOT\WEB-INF\web.xml:

  <servlet>
        <servlet-name>TestServlet</servlet-name>
        <servlet-class>TestServlet</servlet-class>
  </servlet>
  <servlet-mapping>
        <servlet-name>TestServlet</servlet-name>
        <url-pattern>/TestServlet</url-pattern>
  </servlet-mapping>

Tomcat port is 8008
When I run http://localhost:8008/TestServlet, it runs correctly.
Apache port is 82
I cannot start it with http://localhost:82/TestServlet. -- The page cannot
be found

My Aache and Tomcat is connected correctly. All JSP files can run on both.
For example, I have a jsp file
C:\Program Files\Apache
Group\Apache2\tomcat\webapps\ROOT\testJSP\testDBPool.jsp.
I can run http://localhost:82/testJSP/testDBPool.jsp
or http://localhost:8008/testJSP/testDBPool.jsp

in workers2.properties, I have:

[uri:/myServlet/*]
group=lb

[uri:/WEB-INF/*]
group=lb

[uri:/WEB-INF/classes/*]
group=lb


Please forward your instruction.

Thanks.


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