Thanks for the quick response Lester.
I thought web.xml might be the key. I have actually already added some
entries to web.xml in order to try to get this to work but I guess I'm not
quite there yet. Here's what I have so far, perhaps somebody can tell me what
I'm doing wrong:
-------------------------
<?xml version="1.0" encoding="ISO-8859-1"?>
<!DOCTYPE web-app
PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/j2ee/dtds/web-app_2_3.dtd";>
<web-app>
<display-name>MOPITT Data Selection</display-name>
<session-timeout>30</session-timeout>
<servlet>
<servlet-name>Servlet</servlet-name>
<servlet-class>Servlet</servlet-class>
</servlet>
<servlet>
<servlet-name>SelectValidator</servlet-name>
<servlet-class>SelectValidator</servlet-class>
</servlet>
</web-app>
-------------------------
Thanks,
James
Lester June Cabrera wrote:
> Hi James,
>
> Tomcat is bundled with a "build" utility. By editing /etc/web.xml in your
> development directory, you should be able to map your servlet class to your
> desired URL.
>
> Lester
>
> At 01:58 AM 9/26/01 -0600, you wrote:
> >I have a servlet which looks at the request, makes sure that there is a
> >Session and the necessary beans included in the Session and then directs
> >to a JSP page. I want to be able to enter a URL and get the servlet
> >(which will direct me to the JSP).
> >
> >I have the JSP in $TOMCAT_HOME/webapps/myapp/Myapp.jsp and the servlet
> >in $TOMCAT_HOME/webapps/myapp/WEB-INF/classes/Servlet.
> >
> >Can anyone tell me how I can set things up so that I can enter a URL and
> >get the servlet to run ? I have tried using URL's such as
> >http://myserver.my.domain:8080/myapp/Servlet and
> >http://myserver.my.domain:8080/myapp/servlet/Servlet but these don't
> >appear to work. I'm stumped.
> >
> >I'm running Tomcat version 3.2.1-1, the OS is Red Hat 7.0.
> >
> >Thanks in advance for any suggestions or insight. Please Cc:
> >[EMAIL PROTECTED] if you can.
> >
> >
> >-James
