Hi Pim, in order to convert a resource to its URI (string), you can use the built-in SPARQL type cast operator xsd:string, e.g.
SELECT *
WHERE {
?x a :CartesianPoint .
LET (?uri := xsd:string(?x)) .
}
The <CartesianPoint> representation is only on the TBC user interface.
Regards,
Holger
On Jan 21, 2010, at 1:49 AM, Helm, P.W. (Pim) van den wrote:
> How can I get the URI of instances of a semantic xml document. I noticed in
> the form each instance has a unique URI, but the instances are always shown
> by there class name.
>
> So in my case sparqling to get all objects of class CartesianPoint via:
> Select *
> where {
> ?x rdf:type :CartesianPoint
> }
>
> shows a column of elements having all the same name ( <CartesianPoint> ).
>
> How can a get the actual URI?
>
> Kind regards,
> Pim
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