Thanks Holger, This works perfectly. ________________________________
From: [email protected] [mailto:[email protected]] On Behalf Of Holger Knublauch Sent: donderdag 21 januari 2010 12:49 To: [email protected] Subject: Re: [tbc-users] Getting the URI of instances Hi Pim, in order to convert a resource to its URI (string), you can use the built-in SPARQL type cast operator xsd:string, e.g. SELECT * WHERE { ?x a :CartesianPoint . LET (?uri := xsd:string(?x)) . } The <CartesianPoint> representation is only on the TBC user interface. Regards, Holger On Jan 21, 2010, at 1:49 AM, Helm, P.W. (Pim) van den wrote: How can I get the URI of instances of a semantic xml document. I noticed in the form each instance has a unique URI, but the instances are always shown by there class name. So in my case sparqling to get all objects of class CartesianPoint via: Select * where { ?x rdf:type :CartesianPoint } shows a column of elements having all the same name ( <CartesianPoint> ). How can a get the actual URI? Kind regards, Pim This e-mail and its contents are subject to the DISCLAIMER at http://www.tno.nl/disclaimer/email.html -- You received this message because you are subscribed to the Google Groups "TopBraid Composer Users" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/topbraid-composer-users?hl=en. This e-mail and its contents are subject to the DISCLAIMER at http://www.tno.nl/disclaimer/email.html--
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