Thx

One of the profiles we use for our cen standard smls is (RDFS+SHACL)
So in a sense if equivalence is relevant here we already model with “2 x 
rdfs:subClassOf”.

Wrt par. 1.5: guess it is ok to assume rdfs-entailment for most shacl 
processors (so that my shacl af rule for doing the same is obsolete/already 
taken care of). Would only be relevant when RDFS-entailment is “OFF”.

The sentence:
“SHACL uses the RDF and RDFS vocabularies, but full RDFS inferencing is not 
required.”

Is a bit unclear: full RDFS inf. is not required does that mean that some 
limited form IS required? Or can there be no rdfs-entailm. at all? And what is 
“full”/”limited”? Etc.

I am unsure whether my scenarios for CHECKING (not inferencing) the 
rdfs:subClassOf relations  could be relevant

Thx for this whole rdfs/shacl discussion, I learned a lot,
Michel



Dr. ir. H.M. (Michel) Böhms
Senior Data Scientist


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Van: topbraid-users@googlegroups.com <topbraid-users@googlegroups.com> Namens 
Irene Polikoff
Verzonden: Wednesday, April 15, 2020 3:16 PM
Aan: topbraid-users@googlegroups.com
Onderwerp: Re: [topbraid-users] equivalence in shacl

Michel,

I do not advise removing subclass statements. SHACL uses them as described here 
https://www.w3.org/TR/shacl/#terminology, see SHACL subclass.

If you want owl:equivalentClass to be understood by a SHACL engine as 2 
subClassOf statements, they need to be translated as 2 subClassOf statements 
prior to providing data for SHACL validation.

How this translation is accomplished is up to you.
Sent from my iPhone

On Apr 15, 2020, at 8:11 AM, 'Bohms, H.M. (Michel)' via TopBraid Suite Users 
<topbraid-users@googlegroups.com<mailto:topbraid-users@googlegroups.com>> wrote:
Oeps I made mistake in order, right below:


Hi Irene, David

Thx, I had been reading this example about 10 times to understand (indeed 
allvaluesfrom being “at least” not “only” ).

Another thing I have been chewing on: the simple case and especially the 
remarks by David wrt RDFS-entailment.


My original (very) simple case was: I have two ontologies with different name 
space and I want to relate concepts from one to the other saying that they are 
the same. In owl I use owl:equivalentClass and the question was  how best in 
shacl.

I like your split in three cases:
1. Inference like in owl now in shacl (like triple construct)
2. Checking the OWL Restriction in owl meaning (although always compromised by 
CWA nature as you indicated
3. Stronger checking that might be better reflect what you want in CWA fashion: 
ie allvaluesfrom: “at least” becomes “only”)

I am a bit in doubt about option 2, it always seems compromised (?) and chances 
are that you actually want 3. So I most like the split in choice 1 and 3.

Now about the simple case.

ex1:ClassX owl:equivalentClass ex2:ClassY (so no restrictions involved)

Or even simpler:

ex:ClassX owl:equivalentClass ex:ClassY

Or even simpler:

ex:ClassX rdfs:subClassOf ex:ClassY AND
ex:ClassY rdfs:subClassOf ex:ClassX

Let’s focus on the first only:

ex:ClassX rdfs:subClassOf ex:ClassY


Is it true that I could apply your three options here too? (even now that no 
restrictions apply) like:

Option 1: Inference

1a: do nothing in shacl, assume a priori RDFS-entailment

1b: In SHACL AF: tripleconstruct self/rdf:type/ClassY

Option 2: SHACL SHAPE: sh:property (path rdf:type, sh:in (ex:ClassY, ...... 
fixed list, maybe all classes in ont)

Option 3: SHACL SHAPE: sh:property (path rdf:type, sh:hasValue ex:ClassY)


Do I understand the mails between you and David right that they were about 
option 1a or 1b?
(David: a, you: b)

In case of option 1b, 2 and 3: could you then actually delete the 
rdfs:subClassOf clauses in your shacl code (leaving only rdfs class 
definitions? Well ...assuming there are similar decisions for 
rdfs:subPropertyOf). Or is the pure owa treatment/inference with of 
rdfs:subClassOf always a reason to leave it in anyway?


Or....am I talking complete nonsense now 😊

Thx a lot, Michel















Dr. ir. H.M. (Michel) Böhms
Senior Data Scientist

T +31888663107
M +31630381220
E michel.bo...@tno.nl<mailto:michel.bo...@tno.nl>

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Van: topbraid-users@googlegroups.com<mailto:topbraid-users@googlegroups.com> 
<topbraid-users@googlegroups.com<mailto:topbraid-users@googlegroups.com>> 
Namens Irene Polikoff
Verzonden: Wednesday, April 15, 2020 6:51 AM
Aan: topbraid-users@googlegroups.com<mailto:topbraid-users@googlegroups.com>
Onderwerp: Re: [topbraid-users] equivalence in shacl

Actually, I have to correct myself. Because of OWA, you would not get this 
inference since there is no way to know that all values come from the class 
person.

So, I don’t really know under what circumstances one would use this type of 
restriction.

On Apr 14, 2020, at 10:43 AM, Irene Polikoff 
<ir...@topquadrant.com<mailto:ir...@topquadrant.com>> wrote:

Let’s say your data is just:

ex:Alice ex:parent ex:Bob.
ex:Bob a ex:Person.

Now, with OWL we would get an inference {ex:Alice a ex:Person}.

To get this inference in SHACL, you would need something like:

ex:PersonRulesShape a sh:NodeShape ;
sh:targetSubjectOf ex:parent ;
sh:rule [
  a sh:TripleRule ;
  sh:subject sh:this ;
  sh:predicate rdf:type ;
  sh:object ex:Person ;
  ] ;
  sh:condition ex:HasPersonParentShape. # Rule only applies to subjects of a 
triple where objects are persons

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