You could use split() to split the contents of the file into a list of strings.
###
>>> x = 'asdf foo bar foo'
>>> x.split()
['asdf', 'foo', 'bar', 'foo']
###
Here's one way to iterate over that to get the counts. I'm sure there are
dozens.
###
>>> x = 'asdf foo bar foo'
>>> counts = {}
>>> for word in x.split():
... counts[word] = x.count(word)
...
>>> counts
{'foo': 2, 'bar': 1, 'asdf': 1}
###
The dictionary takes care of duplicates. If you are using a really big file,
it might pay to eliminate duplicates from the list
before running x.count(word)
Thanks,
Ryan
-----Original Message-----
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Ron Nixon
Sent: Tuesday, February 15, 2005 11:22 AM
To: tutor@python.org
Subject: [Tutor] count words
I know that you can do this to get a count of home
many times a word appears in a file
f = open('text.txt').read()
print f.count('word')
Other than using a several print statments to look for
seperate words like this, is there a way to do it so
that I get a individual count of each word:
word1 xxx
word2 xxx
words xxx
etc.
__________________________________
Do you Yahoo!?
Yahoo! Mail - Find what you need with new enhanced search.
http://info.mail.yahoo.com/mail_250
_______________________________________________
Tutor maillist - Tutor@python.org
http://mail.python.org/mailman/listinfo/tutor
_______________________________________________
Tutor maillist - Tutor@python.org
http://mail.python.org/mailman/listinfo/tutor
