On Wed, 6 Apr 2005, Tony Meyer wrote:
> > >>> s = 'Hi "Python Tutors" please help'
> > >>> s.split()
> > ['Hi', '"Python', 'Tutors"', 'please', 'help']
> > >>>
> >
> > I wish it would leave the stuff in quotes in tact:
> >
> > ['Hi', '"Python Tutors"', 'please', 'help']
>
> You can do this with a regular expression:
>
> >>> import re
> >>> re.findall(r'\".*\"|[^ ]+', s)
> ['Hi', '"Python Tutors"', 'please', 'help']
>
> The regular expression says to find patterns that are either a quote (\")
> then any number of any characters (.*)then a quote (/") or (|) more than one
> of any character except a space ([^ ]).
Yes! I'll do that. Thank you, especially, for the explanation.
Thanks folks for all the suggestions.
Python attracts the best people!
Marilyn Davis
>
> Or you can just join them back up again:
>
> >>> combined = []
> >>> b = []
> >>> for a in s.split():
> ... if '"' in a:
> ... if combined:
> ... combined.append(a)
> ... b.append(" ".join(combined))
> ... combined = []
> ... else:
> ... combined.append(a)
> ... else:
> ... b.append(a)
> ...
> >>> b
> ['Hi', '"Python Tutors"', 'please', 'help']
>
> (There are probably tidier ways of doing that).
>
> Or you can do the split yourself:
>
> def split_no_quotes(s):
> index_start = 0
> index_end = 0
> in_quotes = False
> result = []
> while index_end < len(s):
> if s[index_end] == '"':
> in_quotes = not in_quotes
> if s[index_end] == ' ' and not in_quotes:
> result.append(s[index_start:index_end])
> index_start = index_end + 1
> index_end += 1
> if s[-1] != ' ':
> result.append(s[index_start:index_end])
> return result
>
> >>> print split_no_quotes(s)
> ['Hi', '"Python Tutors"', 'please', 'help']
>
> =Tony.Meyer
>
>
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