On Wed, 4 Jan 2006, John Fouhy wrote:
> On 04/01/06, Terry Carroll <[EMAIL PROTECTED]> wrote:
> > I hope someone more artful than I can show a quick and easy way to convert
> > either '758C87F3' or -1972144115 to the '8A73780D' that is your goal.
>
> Hmm, well,
>
> >>> i = -1972144115
> >>> '%X' % (pow(2, 32)-(~i+1))
> '8A73780D'
Aha, I also figured another way myself in the meantime:
>>> import win32api
>>> CD_Info = win32api.GetVolumeInformation("D:/")
>>> serno = CD_Info[1]
>>> serno_str = "%X" % (0x100000000+serno)
>>> serno_str
'8A73780D'
>>>
> >>> cdi = win32api.GetVolumeInformation('D:/')
> >>> '%X' % cdi[1]
> '49BC31DB'
>
> So, on my system (ActivePython 2.4, WinXPpro) there is no need for magic.
I think you just got lucky that your first digit (4) was in the range 0-7,
and so didn't generate a negative.
But you *do* point out a fault in my approach. I'll give an incorrect
result for a non-negative. I think the correct way is:
>>> import win32api
>>> CD_Info = win32api.GetVolumeInformation("D:/")
>>> serno = CD_Info[1]
>>> if serno < 0:
... serno_str = "%X" % (0x100000000+serno)
... else:
... serno_str = "%X" % serno
...
>>> serno_str
'8A73780D'
>>>
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