Hi Chris,
On 11/08/06, Christopher Spears <[EMAIL PROTECTED]> wrote:
> def plays(self):
> self.choice = raw_input("Pick (R)ock, (P)aper, or
> (S)cissors! ")
> if self.choice == 'r':
> self.choice = 'rocks'
> elif self.choice == 'p':
> self.choice = 'paper'
> elif self.choice == 's':
> self.choice = 'scissors'
> else:
> print "Invalid response"
A couple of comments here ---
Firstly, to me, 'self.choice' is the thing you want to save, which is
distinct from the user's input. So, I would call the result of
raw_input something else. eg:
fromUser = raw_input("Pick (R)ock, (P)aper, or
(S)cissors! ")
if fromUser == 'r':
self.choice = 'rocks'
# etc
Secondly, if the user enters 'R' (as you request), your program will
say "Invalid response", because 'R' != 'r'. You can get around this
by saying:
if fromUser.lower() == 'r':
Thirdly, a dictionary would make this much simpler. Something like:
translate = { 'r':'rock', 's':'scissors', 'p':'paper' }
try:
self.choice = translate[fromUser.lower()]
except KeyError:
print 'Invalid response.'
# what else are you going to do? what does self.choice become?
> def compare_objects(human, computer):
> print "Human picked ", human.choice
> print "Computer picked", computer.choice
> if human.choice == computer.choice:
> print "Draw!"
> elif human.choice == 'rocks' and computer.choice ==
> 'paper':
> print "Computer wins!"
> computer.points = computer.points + 1
[...]
You can use a similar dictionary-based approach here. You could use a
dictionary to make a data structure that expresses what beats what,
and then reduce your code to:
if human.choice == computer.choice:
print 'Draw!'
elif # human beats computer
print 'Human wins!'
else:
print 'Computer wins!'
HTH :-)
--
John.
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