Kent Johnson wrote: > Robert Hicks wrote: >> This is the loop code: >> >> for line in f2: >> for id in idList: >> if id in line: >> print "%s: %s" % (id, f2.next()) >> found = "%s: %s" % (id, f2.next()) >> f3.write(found) >> >> >> I have an list, idList[], that contains a list of id numbers. That code >> will loop the the f2 file and for lines that have an id on it it will >> print the "next" line (so I can see what it is doing) and write it to a >> file. I will turn off that screen print after I get it going the way I >> want it to. > > I don't see any particular reason this should be slow unless idList is > large. Perhaps the output is being buffered somewhere and not appearing > until the process is done? How are you running the program? > > BTW the line that you print and the line that you save to the file are > not the same; every time you call f2.next() it will fetch another line > from the file. If you want them to be the same you could say > found = "%s: %s" % (id, f2.next()) > print found > f3.write(found) >
Thanks for that! idList only has about 129 id numbers in it. I am running it straight from a Linux console. I thought about buffering but I am not sure how Python handles that. Do you know if Python has a "slower" startup time than Perl? That could be part of it though I suspect the buffering thing more. Robert _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
