Greetings,
Many thanks to wormwood_3 and Kent for their help.
Summary:
The working script looks like this:
# the lines with '<script type' are deleted.
import fileinput
for i in range(1, 176):
filename = 'filename%04d.html' % i
for line in fileinput.input(filename, inplace=1):
#for line in fileinput.input("file0001.html", inplace=1):
line = line.strip()
if not '<script type'in line:
print line
It was implemented as:
$ python delete.py
...and it took less than a second to delete the line from all the files!
I'm working on the files in a temporary directory, so I'm going to try
the other solution as well.
Happy Programming!
--
bhaaluu at gmail dot com
On 9/14/07, Kent Johnson <[EMAIL PROTECTED]> wrote:
> bhaaluu wrote:
> > On 9/13/07, wormwood_3 <[EMAIL PROTECTED]> wrote:
> >
> >> I think the problem is that the original script you borrowed looks
> >> at
> the file passed to input, and iterates over the lines in that file,
> removing them if they match your pattern. What you actually want to be
> doing is iterating over the lines of your list file, and for each line
> (which represents a file), you want to open *that* file, do the check
> for your pattern, and delete appropriately.
> >
> > This is exactly what I'd like to do. =)
> > After manually opening about 25 files individually and deleting the line
> > that I wanted to delete, and seeing about 175 files left to finish, I
> > thought
> > to myself, 'I'm learning Python! Python is supposed to be really good at
> > this kind of stuff.'
>
> Good idea! Python is excellent for this kind of stuff.
>
>
> > The 'fileinput' snippet is one solution, but I'd rather be able to pass it a
> > list of filenames to work on, rather than have to manually change the
> > filename in the snippet each time. The files are numbered, in order,
> > from 0001 to 0175, (filename0001.html to filename0175.html).
>
> Sam has already given you one solution - to pass the list of filenames
> on the command line.
>
> The first argument to fileinput.input() can be a list of filenames, so
> you could do
>
> filenames = open("filelist.list").read().splitlines()
> for line in fileinput.input(filenames, inplace=1):
> # etc
>
> > One thought was to be able to change the filename number incrementally,
> > assign it to a variable, and run it through a for loop? Isn't it amazing
> > how a Newbie approaches a problem? =)
>
> That is arguably a better approach than reading the file, since it
> avoids the effort of creating the file.
>
> for i in range(1, 176):
> filename = 'filename%04d.html' % i
> for line in fileinput.input(filename, inplace=1):
> # etc
>
> Kent
>
--
bhaaluu at gmail dot com
_______________________________________________
Tutor maillist - [email protected]
http://mail.python.org/mailman/listinfo/tutor
