Hello Bryan! On Wednesday 14 November 2007 00:18, Bryan Fodness wrote: > I see how to do it in a one-dimenstional array, but do not know the > syntax for the multi-dimensional case. > > >from numpy import * > > a = zeros((60,40), int) > > fields = {} > field = 10 > fields[field] = '30A', 5 > > iy = int(fields[field][1]) > ix = int(fields[field][0].rstrip('AB')) > > for j in range(iy): > put(a,[39 - j],[1]) Should be maybe: a[0, 39 - j] = 1
> > Can someone help me figure out how I would do it for multiple rows? > > I thought, > > for i in range(ix): > for j in range(iy): > put(a,[i][39-j],[1]) change to: a[i, 39-j] = 1 You could replace the nested for loops by the following code: a[:ix, :iy:-1] = 1 I think you shouldn't use put(...) in your code. It is a fairly specialized function. More information: http://www.scipy.org/Numpy_Example_List_With_Doc#head-5202db3259f69441c695ab0efc0cdf45341829fc Regards, Eike _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor