Thank you. That works great!
On Nov 13, 2007 7:18 PM, Eike Welk <[EMAIL PROTECTED]> wrote: > Hello Bryan! > > On Wednesday 14 November 2007 00:18, Bryan Fodness wrote: > > I see how to do it in a one-dimenstional array, but do not know the > > syntax for the multi-dimensional case. > > > > >from numpy import * > > > > a = zeros((60,40), int) > > > > fields = {} > > field = 10 > > fields[field] = '30A', 5 > > > > iy = int(fields[field][1]) > > ix = int(fields[field][0].rstrip('AB')) > > > > for j in range(iy): > > put(a,[39 - j],[1]) > Should be maybe: > a[0, 39 - j] = 1 > > > > > Can someone help me figure out how I would do it for multiple rows? > > > > I thought, > > > > for i in range(ix): > > for j in range(iy): > > put(a,[i][39-j],[1]) > change to: > a[i, 39-j] = 1 > > You could replace the nested for loops by the following code: > a[:ix, :iy:-1] = 1 > > I think you shouldn't use put(...) in your code. It is a fairly > specialized function. > > More information: > http://www.scipy.org/Numpy_Example_List_With_Doc#head-5202db3259f69441c695ab0efc0cdf45341829fc > > Regards, > Eike > _______________________________________________ > Tutor maillist - Tutor@python.org > http://mail.python.org/mailman/listinfo/tutor > _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor