> > But if you don't have l1 defined yet, you can't add to l2 > It's like: > def a2(): > l1 = foo + l2 > > UnboundLocalError: local variable 'foo' referenced before assignment > > It's because l1 (and foo at above example) is a local variable. > a1's l1 is different from a2's l1. > > > Sorry to be dense, but how, in what way, is a1's l1 different from a2's > l1"? Both are [1,2,3]*100 . > > Both contain same value, but are in different namespaces (so, different context and different memory areas).
If you do a="spam" and b="spam", this doesn't make them same variable, they just have same value. So is in that code. But to make it more confusing, names were the same. Douglas
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