At 12:11 AM 6/28/2008, Douglas Drumond wrote:
- But if you don't have l1 defined yet, you can't add to l2
- It's like:
- def a2():
- l1 = foo + l2
- UnboundLocalError: local variable 'foo' referenced before assignment
- It's because l1 (and foo at above example) is a local variable.
- a1's l1 is different from a2's l1.
Sorry to be dense, but how, in what way, is a1's l1 different from a2's l1"? Both are [1,2,3]*100 .
Both contain same value, but are in different namespaces (so, different context and different memory areas).
If you do a="spam" and b="spam", this doesn't make them same variable, they just have same value.
So is in that code. But to make it more confusing, names were the same.
No I didn't mean that they were the same variable, but that they had the same value, and both appear in the same form just below the if __name__ == '__main__': below their respective functions.
Dick
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