On Thu, Oct 30, 2008 at 11:03 PM, Peter Anderson <
[EMAIL PROTECTED]> wrote:
> My problem is with the actual entry of the ASCII codes. My solution has a
> "if" test to remove the leading "0" from an input of say "033". With this
> test the output of the decode is correct in printing "!". Without the "if"
> test the output is "\x1b" at best or a run-time error for other numbers.
That is because the leading 0 marks the number as octal when eval()
interprets it as a number.
> My question is this: is there a better way to convert raw input of say
> "033" to "33" than what I have used? Thanks in advance for any help.
Dj's use of int() is the best way to do this. For future reference, the easy
way to strip leading 0's from a string is with lstrip():
In [5]: '033'.lstrip('0')
Out[5]: '33'
Kent
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