The try: except: clauses allow for someone typing something like
'spam' when the program expects a number. It stops the program dying
with an error message.
---
Richard "Roadie Rich" Lovely
Part of the JNP|UK Famille
www.theJNP.com
---
(Sent from my iPod - please allow for any typos: it's a very small
keyboard)
On 31 Oct 2008, at 18:50, bob gailer <[EMAIL PROTECTED]> wrote:
Peter Anderson wrote:
Dj Gilcrease wrote:
The simple answer is to just use chr(int(inNum))
though here is how I would do it
def convert_string_to_int(strInt):
try:
return int(strInt)
except ValueError:
return 0
def getNumbers(output):
inNum = raw_input("Please enter an ASCII number\n(33 - 126,
[Enter] to quit): ")
ascii_num = convert_string_to_int(inNum)
if ascii_num >= 33 and ascii_num <=126:
output.append(chr(ascii_num))
getNumbers(output)
I would avoid recursion. Save that for recursive algorithms. An
ordinary loop is easier to read/maintain and you will not run out of
recursion depth. Also give user a meaningful error message.
while True:
inNum = raw_input("Please enter an ASCII number\n(33 - 126,
[Enter] to quit): ")
if not inNum:
break
ascii_num = convert_string_to_int(inNum)
if ascii_num >= 33 and ascii_num <=126:
output.append(chr(ascii_num))
else:
print "Input must be an integer in range 33..126"
if __name__ == '__main__':
print "This script converts a sequence of ASCII numbers"
print "into the string of text that it represents."
print
output = []
getNumbers(output)
print output
Dj Gilcrease
OpenRPG Developer
~~http://www.openrpg.com
Dj,
Thanks for the suggestions; both work perfectly. Can I ask a
supplementary question please?
In the def convert_string... function why do you include the
"except ValueError: / return 0" clause?
try: must be followed by except or finally.
--
Bob Gailer
Chapel Hill NC 919-636-4239
When we take the time to be aware of our feelings and needs we have
more satisfying interatctions with others.
Nonviolent Communication provides tools for this awareness.
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