"bob gailer" <bgai...@gmail.com> wrote
Also consider that the sum of consecutive integers between 1 and n
is n*(n+1)/2.
Calculate that for 1..333 then multiply by 3
Calculate that for 1..199 then multiply by 5
add those
Calculate that for 1..66 then multiply by 15
subtract that from the total
Ooh, that's sneaky! I haven't seen that before.
Took me a couple of reads through to figure out how it worked :-)
--
Alan Gauld
Author of the Learn to Program web site
http://www.alan-g.me.uk
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