On Sun, Jan 4, 2009 at 3:43 AM, Benjamin Serrato <benjamin.serr...@gmail.com> wrote:
> I think it does what I wanted it to do, but Kent pointed out I wanted > it to do was a false solution. So, I can create a list of all common > multiples below 1000, sum them, subtract them from 266 333. Or, what > I prefer, create a list of all multiples, checking against that list > for a multiple before adding a new multiple. But, I don't know how to > work with lists so I'll be back in a day or two. Removing this double counting can be done easily if you realize that the double multiples are exactly 15 and its multiples. -- André Engels, andreeng...@gmail.com _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
