Hey Senthil,Thanks for your response. My script is similar to yours, but as
you've pointed that it could be temporary. I've been retrying to connect and
send email but in vain.Here's the snippet of my code. Can you debug and help me
what could really have gone wrong.import smtplibimport base64smtpserver =
'smtp.gmail.com'AUTHREQUIRED = 0 # if you need to use SMTP AUTH set to
1smtpuser = 'u...@gmail.com'# for SMTP AUTH, set SMTP username heresmtppass =
'*****'# for SMTP AUTH, set SMTP password hereRECIPIENTS =
['someu...@gmail.com']SENDER = 'someu...@gmail.com'mssg = open('mssg.txt',
'r').read() # I am reading from this file on the same directorysession =
smtplib.SMTP(smtpserver,'465')session.ehlo()#session.esmtpfeatures["auth"] =
"LOGIN
PLAIN"session.connect(smtpserver,'465')session.ehlo()session.starttls()session.setdebuglevel(1)session.helo()if
AUTHREQUIRED:try:session.login(smtpuser, smtppass)except
SMTPAuthenticationError, e:# if login fails, try again using a manual pla
in login methodsmtp.docmd("AUTH LOGIN", base64.b64encode( smtpuser
))smtp.docmd(base64.b64encode( smtppass ), "")smtpresult =
session.sendmail(SENDER, RECIPIENTS, mssg)if smtpresult:errstr = ""for recip in
smtpresult.keys():errstr = """Could not delivery mail to: %sServer said:
%s%s%s""" % (recip, smtpresult[recip][0], smtpresult[recip][1], errstr)raise
smtplib.SMTPException, errstr This is the Stack Trace I got when I ran the
above script after a very long time(>15min)Traceback (most recent call last):
File "C:\Python26\Mail.py", line 13, insession = smtplib.SMTP(smtpserver,'465')
File "C:\Python26\lib\smtplib.py", line 239, in init (code, msg) =
self.connect(host, port) File "C:\Python26\lib\smtplib.py", line 296, in
connect (code, msg) = self.getreply() File "C:\Python26\lib\smtplib.py", line
340, in getreply raise SMTPServerDisconnected("Connection unexpectedly closed")
smtplib.SMTPServerDisconnected: Connection unexpectedly closedTool completed
with exit code 1ThanksAvi
nash Original message From:Senthil Kumaran< orsent...@gmail.com >Date: 11 Mar
09 09:58:53Subject:Re: [Tutor] How to send an email using PythonTo: Samuel
Avinash Hello Samuel,When sending through smtp.gmail.com you might need to
starttls() and do a login() before sending.>>> import smtplib >>> headers =
"From: %s\r
To: %s\r
Subject: %s\r
\r
" %(from,to,subject) >>> message = headers + "Hello, How are you?" >>>
mailserver = smtplib.SMTP('smtp.gmail.com') >>> mailserver.ehlo() >>>
mailserver.starttls() >>> mailserver.login('username','password') >>>
mailserver.sendmail(from,to,message)As I try it now, startls() was giving me a
message " reply: '454 TLS not available due to temporary reason\r
'" As the error message says, it could be temporary.Try it at your end and
report if you succeed.Thanks, SenthilOn Tue, Mar 10, 2009 at 4:41 PM, Samuel
Avinashwrote: > Hi, > Can anybody tell me how to send an email to a recipient
using Python > I am trying to send an email using Gmail > I create an instance
ofsmtplib and use : > x=smtplib.SMTP(sever,port) > and then > x.login(user,pwd)
> I try to send the email using > x..sendmail(SENDER, RECIPIENTS, msg) > But I
get the following error > Traceback (most recent call last): > File
"C:UsersAvisDesktopMail.py", line 13, in> session =
smtplib.SMTP(smtpserver,port) > File "C:Python26libsmtplib.py", line 239, in
init > (code, msg) = self.connect(host, port) > File "C:Python26libsmtplib.py",
line 295, in connect > self.sock = self.getsocket(host, port, self.timeout) >
File "C:Python26libsmtplib.py", line 273, in getsocket > return
socket.createconnection((port, host), timeout) > File "C:Python26libsocket.py",
line 498, in createcon
nection > for res in getaddrinfo(host, port, 0, SOCKSTREAM): >
socket.gaierror: [Errno 11001] getaddrinfo failed > > This is in Windows Vista
and I am trying to connect to "smtp.gmail.com" with > port 465 > > Tutor
maillisttu...@python.org > http://mail.python.org/mailman/listinfo/tutor >
>Senthil
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