On Aug 29, 2009, at 12:23 AM, Michael M Mason wrote:
i wrote:
def pack(in_seq):
out_list=[]
x = 1
ll=[1, 1]
for each in in_seq:
ll[0] = x
ll[1] = each
out_list.append(ll)
#print ll
x = x + 1
print out_list
Variable out_list consists of list ll repeated however many times.
Each
time you change ll you're changing it everywhere it appears in
out_list.
That is, what's being appended to out_list isn't a copy of ll, it's a
pointer to ll.
You need something like:-
out_list.append([ll[0],ll[1]])
Right... ugh.. Totally forgot about that. Python 101. I don't know why
my brain resists
that idea. Every time i let python alone a while and come back to it i
get bit by this.
And you need to add a return at the end of the function, otherwise it
returns None:
return out_list
That, of course, i know... I was messing around debugging of course.
Thanks for the response.
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