On Mon, Jul 5, 2010 at 11:24 PM, Vineeth Rakesh <vineethrak...@gmail.com>wrote:
> Hello all, > > Can some one help me to return a special pattern from a list. > > say list = > ["something1.mp3","something2.mp3","something4.pdf","something5.odt"] > One suggestion. Don't name a list as list. Use l or List or any other variable name. list is one of the syntax in python. > > now say I just need to return the files with .mp3 extension. How to go > about doing this? > >>> list = ["something1.mp3","something2.mp3","something4.pdf","something5.odt"] >>> [i for i in list if i[-4:] == '.mp3'] ['something1.mp3', 'something2.mp3'] or may be , >>> [i for i in list if os.path.splitext(i)[0] == '.mp3'] # If you want to deal with file extentions, that is. For smaller case string is good, for obscure patter, you can try regex module. ~l0nwlf
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