On Mon, Jul 5, 2010 at 11:58 PM, Shashwat Anand <anand.shash...@gmail.com>wrote:
> > > On Mon, Jul 5, 2010 at 11:24 PM, Vineeth Rakesh > <vineethrak...@gmail.com>wrote: > >> Hello all, >> >> Can some one help me to return a special pattern from a list. >> >> say list = >> ["something1.mp3","something2.mp3","something4.pdf","something5.odt"] >> > > One suggestion. Don't name a list as list. Use l or List or any other > variable name. list is one of the syntax in python. > > >> >> now say I just need to return the files with .mp3 extension. How to go >> about doing this? >> > > >>> list = > ["something1.mp3","something2.mp3","something4.pdf","something5.odt"] > >>> [i for i in list if i[-4:] == '.mp3'] > ['something1.mp3', 'something2.mp3'] > > or may be , > >>> [i for i in list if os.path.splitext(i)[0] == '.mp3'] # If you want to > deal with file extentions, that is. > Oops, sorry for the typo. It'll be , >>> [i for i in list if os.path.splitext(i)[1] == '.mp3'] > For smaller case string is good, for obscure patter, you can try regex > module. > > ~l0nwlf >
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