> I have this : > > def sort_sequence(seq): > """ > >>> sort_sequence([3, 4, 6, 7, 8, 2]) > [2, 3, 4, 6, 7, 8] > >>> sort_sequence((3, 4, 6, 7, 8, 2)) > (2, 3, 4, 6, 7, 8) > >>> sort_sequence("nothappy") > 'ahnoppty' > """ > if type(seq) == type([]): > seq.sort() > elif type(seq)== type(()): > seq = tuple(sorted(seq)) > else: > seq2 = list(seq) > seq2.sort() > print seq2 > seq.join(seq2) > return seq > > The problem is that if I want to sort the characters in a string, the list > exist of the sorted characters but as soon as I convert them to a string I > get the old string.
Carefully read the documentation for str.join: http://docs.python.org/library/stdtypes.html#str.join How does it work, what does it return, etc. Then fix the corresponding line in your code. As a hint: str.join does work quite different than list.sort; I assume you're confusing their syntaxes. Good luck, Evert > > What went wrong ? > > Roelof > > _______________________________________________ > Tutor maillist - Tutor@python.org > To unsubscribe or change subscription options: > http://mail.python.org/mailman/listinfo/tutor _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor