> Subject: Re: [Tutor] sort problem
> From: evert....@gmail.com
> Date: Wed, 8 Sep 2010 17:26:58 +0200
> CC: tutor@python.org
> To: rwob...@hotmail.com
>
> > I have this :
> >
> > def sort_sequence(seq):
> > """
> > >>> sort_sequence([3, 4, 6, 7, 8, 2])
> > [2, 3, 4, 6, 7, 8]
> > >>> sort_sequence((3, 4, 6, 7, 8, 2))
> > (2, 3, 4, 6, 7, 8)
> > >>> sort_sequence("nothappy")
> > 'ahnoppty'
> > """
> > if type(seq) == type([]):
> > seq.sort()
> > elif type(seq)== type(()):
> > seq = tuple(sorted(seq))
> > else:
> > seq2 = list(seq)
> > seq2.sort()
> > print seq2
> > seq.join(seq2)
> > return seq
> >
> > The problem is that if I want to sort the characters in a string, the list
> > exist of the sorted characters but as soon as I convert them to a string I
> > get the old string.
>
> Carefully read the documentation for str.join:
> http://docs.python.org/library/stdtypes.html#str.join
>
> How does it work, what does it return, etc. Then fix the corresponding line
> in your code.
> As a hint: str.join does work quite different than list.sort; I assume you're
> confusing their syntaxes.
>
> Good luck,
>
> Evert
>
str.join(iterable)ΒΆ
How it works.
It puts all the elements of iterable into one string named str.
So it returns a string.
Str is here seq and the iterable is the list made by list.sort so seq2
So I don't see the error in that line.
Roelof
_______________________________________________
Tutor maillist - Tutor@python.org
To unsubscribe or change subscription options:
http://mail.python.org/mailman/listinfo/tutor
