On Thu, Sep 9, 2010 at 2:21 PM, Roelof Wobben <rwob...@hotmail.com> wrote:
> Hello, > > I have this : > > def recursive_count(target, nested_num_list): > """ > >>> recursive_count(2, [2, 9, [2, 1, 13, 2], 8, [2, 6]]) > 4 > >>> recursive_count(7, [[9, [7, 1, 13, 2], 8], [7, 6]]) > 2 > >>> recursive_count(15, [[9, [7, 1, 13, 2], 8], [2, 6]]) > 0 > >>> recursive_count(5, [[5, [5, [1, 5], 5], 5], [5, 6]]) > 6 > """ > for element in nested_num_list: > if type(element) == type([]): > test = recursive_count(target, element) > print element, target > if element == target : > count = count + 1 > return count > > if __name__ == "__main__": > import doctest > doctest.testmod() > > > Now I get this message : > > UnboundLocalError: local variable 'count' referenced before assignment > It is because you are doing count = count + 1 But where is count defined. > > But if I do this : > > def recursive_count(target, nested_num_list): > """ > >>> recursive_count(2, [2, 9, [2, 1, 13, 2], 8, [2, 6]]) > 4 > >>> recursive_count(7, [[9, [7, 1, 13, 2], 8], [7, 6]]) > 2 > >>> recursive_count(15, [[9, [7, 1, 13, 2], 8], [2, 6]]) > 0 > >>> recursive_count(5, [[5, [5, [1, 5], 5], 5], [5, 6]]) > 6 > """ > count = 0 > for element in nested_num_list: > if type(element) == type([]): > test = recursive_count(target, element) > print element, target > if element == target : > count = count + 1 > return count > > if __name__ == "__main__": > import doctest > doctest.testmod() > > The count will always be 0 if a nested list is being found. > > What's the python way to solve this > I am not sure what do you want to achieve by this ? What is the problem statement ? > > Roelof > > > _______________________________________________ > Tutor maillist - Tutor@python.org > To unsubscribe or change subscription options: > http://mail.python.org/mailman/listinfo/tutor > > -- ~l0nwlf
_______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
