On 9 September 2010 12:59, Shashwat Anand <[email protected]> wrote:
> > Let's say n, l = 2, [2, 9, [2, 1, 13, 2], 8, [2, 6]] > Simply Flatten the list l, which will be then be; flatten(l) = [ 2, [2, 9, > 2, 1,13, 2, 8, 2, 6 ] > Now count for n; flatten.count(n) > > This is fine except that the excercise probably has to do with introducing recursion and scoping, which is unfortunately defeated by this solution. Roelof, look at what you do with the result of the recursive call which you currently assign to test and otherwise ignore -- you want to add this to count and/or return it... Walter
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