From: tutor-bounces+bermanrl=cfl.rr....@python.org
[mailto:tutor-bounces+bermanrl=cfl.rr....@python.org] On Behalf Of Dawn Samson
Sent: Sunday, November 14, 2010 5:17 PM
To: tutor@python.org
Subject: [Tutor] While Loops: Coin Flip Game
>>>>
Greetings,
I'm a Python beginner and working my way through Michael Dawson's Python
Programming for the Absolute Beginner
import random
# set the coin
coin = random.randrange(2)
headsCount = 0
tailsCount = 0
count = 0
# the loop
while count <= 100:
coin
if coin == 0:
headsCount += 1
if coin == 1:
tailsCount += 1
count += 1
print "The number of heads was", heads
print "The number of tails was", tails
raw_input("\n\nPress the enter key to exit.")
Thanks,
S. Dawn Samson
>>>>>
Hi,
Think in terms of logical steps. You need to generate the results of a random
coin toss for every toss of the coin. Therefore, if you are tossing 100
tosses, you need to generate 100 results based on a probability of zero or
one.
Since this is your homework assignment you write the code, but in terms of a
logical frame work you would have something like the following.
Tossknt = 1
Generate a random toss ; results being either one or 0. Further , assume 0 is
tail; heads is one.
If toss = 1 headcount = headcount + 1
Else tailcount = tailcount + 1
Tossknt = Tossknt + 1
If Tossknt < 100 Continue loop
Else print nbr of heads tossed = , headcount
Print nbr of tails tossed = , tailcount
Obviously, this is not valid python code but it should give you enough
information to solve your problem.
Good luck,
Robert
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