On 11/23/2010 8:22 AM Alan Gauld said...
"Richard D. Moores" <[email protected]> wrote
it was the way to go over "if n % 2 == 0". By my tests, it's 4.3% to
9.5% faster, depending on the integer tested - size and whether odd or
even. See the speed testing script and results at
<http://tutoree7.pastebin.com/iragLgDz>.
Did you try:
if n % 2: pass
else: do it here?
or
def x2(n):
return not (n % 2)
Emile
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