----- Original Message ----- 
  From: Pacific Morrowind 
  To: tutor@python.org 
  Sent: Thursday, February 24, 2011 10:21 PM
  Subject: Re: [Tutor] list of dictionary


  Hi;

  On 24/02/2011 9:35 PM, sunil tech wrote: 
    Hi all...

    i have d=[{'qty':0.0},{'qty':0.0}



  If there isn't some pressing reason to dictionaries as the list items (but 
since I'm not sure how you're generating the list/what you are later using the 
list I can't tell ofc but 

  Hi - I had just a couple comments plus clarification about lists and 
iterating:  

  if applicable to your situation I'd suggest just doing for creation of the 
list
   d = []

  I like creating the empty variable structure, makes the code really clear. 

  (logic for whatever gives your values)
  d.append(value)
  etc.)

    when all the qty is 0.0,
    i want to perform some print operation
    (only at once, after it checks everything in the list of dictionary 'd')...

    if its not 0.0,
    print some message...

    Thank you in advance

  Presuming you do have to use the dictionaries:
  qty = 0.0
  for item in d:

  Right here - is the variable 'item' created right on the spot to iterate over 
this list?  And I think you are doing the same thing when you create the 
variable 'subitem' in the line below, right?  I am  trying to get myself to 
recognize an iterator variable as opposed to a counter variable I create myself 
 to keep track of these things (used in other programming languages) - and 
realizing the difference between counter/iterator variables and variables that 
I really care about like 
   'd = []' .

  Thanks!

  Patty


      for subitem in d:
          if item[subitem] != 0.0:
              qty = item[subitem]
              break
  if qty != 0.0:
      print "some message - for example a non zero qty = %f" % qty

  (presuming you are using Python 2x - if using python 3x the syntax will be 
slightly different)
  Hopefully that will serve your purpose if not just post again and I or one of 
the more frequently posting helpful users here will answer soon.
  Nick




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