On Thu, Sep 22, 2011 at 10:27 AM, Joel Knoll <[email protected]> wrote:
> Given a range of integers (1,n), how might I go about printing them in the > following patterns: > > 1 2 3 4 ... n > 2 3 4 5 ... n 1 > 3 4 5 6 ... n 1 2 > > etc., e.g. for a "magic square". So that for the range (1,5) for example I > would get > > 1 2 3 4 > 2 3 4 1 > 3 4 1 2 > 4 1 2 3 > > I just cannot figure out how to make the sequence "start over" within a > row, i.e. to go from 4 down to 1 in this example. > > I have been grappling with this problem for 2.5 days and have gotten > nowhere! > > _______________________________________________ > Tutor maillist - [email protected] > To unsubscribe or change subscription options: > http://mail.python.org/mailman/listinfo/tutor > > I would probably do something like this: a = [1,2,3,4] > print a > b = a.pop(0) > a.append(b) > print a Probably an easier way of doing it though. If you wanted to do that four times: for item in a: > print a > b = a.pop(0) > a.append(b) You just need to think of it as a register and shifting bits left or right
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