On 09/22/2011 10:43 AM, Hugo Arts wrote:
forgot to forward to list:
From: Hugo Arts<[email protected]>
Date: Thu, Sep 22, 2011 at 4:42 PM
Subject: Re: [Tutor] range question
To: [email protected]
On Thu, Sep 22, 2011 at 4:37 PM, Dave Angel<[email protected]> wrote:
On 09/22/2011 10:27 AM, Joel Knoll wrote:
Given a range of integers (1,n), how might I go about printing them in the
following patterns:
1 2 3 4 ... n2 3 4 5 ... n 13 4 5 6 ... n 1 2
etc., e.g. for a "magic square". So that for the range (1,5) for example I
would get
1 2 3 42 3 4 13 4 1 24 1 2 3
I just cannot figure out how to make the sequence "start over" within a row,
i.e. to go from 4 down to 1 in this example.
I have been grappling with this problem for 2.5 days and have gotten
nowhere!
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Seems like the easiest way would be to duplicate the range once (so you have
a list twice as long), and then use various slices of it.
x = list(range(1, 5)) #could omit the list() function in python 2.x
x2 = x+x
for the nth row, use
row = x2[n:n+n]
Surely you meant to type:
x = list(range(1, 6))
x2 = x + x
row = x[n:n+len(x)]
The second correction is important, the first one wrong. The OP's
example was looking for the numbers 1 through 4, so range(1,5) was correct.
--
DaveA
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