On 07/03/2012 04:36, col speed wrote:
On 7 March 2012 10:45, Mark Lawrence<breamore...@yahoo.co.uk> wrote:
On 07/03/2012 03:24, col speed wrote:
Hello again
Hope you are all well.
I'm trying to make a "match 3" game, where you have a square grid and
have to put 3 matching shapes in a row.
I need a function that tells me if the game is playable, ie. it is
possible to match 3 shapes by only swapping 2 adjacent shapes.
I have looked at the co-ordinates and got a list of the "offset
co-ordinates" needed for the above.
I have a list of coordinates and a list of "lemons" and I want to see
if *any* lemon coordinate is in the list of coordinates.
I tried this:
if any(((x+1, y+1), (x-1, y+2),(x-2, y+1),(x-1, y-1 ))) in fruit_type:
return True
Thinking that if *any* of the tuples is in fruit_type(a list of
tuples), then it should return True.
However, it always equates to False.
Here's the way to find out.
help(any)
Help on built-in function any in module __builtin__:
any(...)
any(iterable) -> bool
Return True if bool(x) is True for any x in the iterable.
help('in')
Comparisons
***********
[snipped]
For the list and tuple types, ``x in y`` is true if and only if there
exists an index *i* such that ``x == y[i]`` is true.
[snipped]
--
Cheers.
Mark Lawrence.
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Thanks Mark
I looked up help(any), but not help(in)!
Note as it's a keyword it has to be in quotes, help('in').
I *think* I understand:
Where it says:
"For the list and tuple types, ``x in y`` is true if and only if there
exists an index *i* such that ``x == y[i]`` is true."
I suppose I am looking for .....an index *i* and *j* such that x[j] == y[i].
Is that right?
I reckon so although I don't believe that the interactive prompt lies.
>>> a=tuple(range(10))
>>> b=tuple(reversed(a))
>>> a,b
((0, 1, 2, 3, 4, 5, 6, 7, 8, 9), (9, 8, 7, 6, 5, 4, 3, 2, 1, 0))
>>> a[3] == b[3]
False
>>> a[5] == b[4]
True
cheers
Col
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HTH.
--
Cheers.
Mark Lawrence.
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