On 03/07/2012 12:07 AM, col speed wrote:
<snip>
Then we have:
a = tuple(range(10))
b = tuple(reversed(a))
any(a) in b
True
any(b) in a
True
any((a,b)) in (a,b)
False # I think I understand this now, but I must admit it looks confusing!
Thanks again
Col
None of those last three does anything usefully similar to your original
request. Just because an English phrase makes sense, you can't expect
the equivalent set of keywords to do anything remotely related.
If you insist on using the any function in solving your problem, you'll
have to preprocess your two arrays into a single iterator. And at that
point, you might as well solve the problem in that loop.
(untested):
def test(a, b):
for val1 in a:
for val2 in b:
if val1 == val2: return True
return False
print test(a,b)
Rather than:
def findinter(a, b):
res = []
for val1 in a:
for val2 in b:
res.append(val1 == val2)
return res
print any(findinter(a,b))
--
DaveA
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