All, Thanks for the help. On Sat, Apr 14, 2012 at 1:33 PM, Bod Soutar <bod...@googlemail.com> wrote:
> > > On 14 April 2012 18:29, Bod Soutar <bod...@googlemail.com> wrote: > >> >> >> On 14 April 2012 16:27, Tom Tucker <tktuc...@gmail.com> wrote: >> >>> >>> Hello all. Any suggestions how I could easily iterate over a list and >>> print the output 3 across (when possible)? One method I was considering >>> was removing the recently printed item from the list, checking list length, >>> etc. Based on the remaining length of the list I would then print X >>> across. Yah? Is their and easier approach I might be overlooking? >>> >>> >>> For example... >>> >>> mylist = ['serverA', 'serverB', 'serverC', 'serverD',' serverE', >>> 'serverF', 'serverG'] >>> >>> >>> Desired Output >>> ============ >>> serverA serverB serverC >>> serverD serverE serverF >>> serverG >>> >>> _______________________________________________ >>> Tutor maillist - Tutor@python.org >>> To unsubscribe or change subscription options: >>> http://mail.python.org/mailman/listinfo/tutor >>> >>> >> How about something like this >> >> >> mylist = ['serverA', 'serverB', 'serverC', 'serverD','serverE', >> 'serverF', 'serverG'] >> tempstr = "" >> count = 0 >> >> for item in mylist: >> count += 1 >> if count == 3: >> tempstr += (i + "\n") >> count = 0 >> else: >> tempstr += (i + " ") >> >> print tempstr >> >> >> The above code prepares an empty string variable, and a count variable. >> On each iteration, it checks to see if the count is equal to 3. If it is, >> then it appends the current list element to the string and also adds a >> newline character("\n"), then the count is reset to 0. If the count isn't >> 3, it simply appends the current list element along with a space. >> >> Hope this helps, >> Bodsda >> >> >> erm, I screwed up my variable names. where you see 'i', this should be > item (or the other way around). > My bad. > > -- Bodsda >
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