On 4/15/2012 10:54 PM, bob gailer wrote:
On 4/14/2012 11:27 AM, Tom Tucker wrote:
Hello all. Any suggestions how I could easily iterate over a list
and print the output 3 across (when possible)? One method I was
considering was removing the recently printed item from the list,
checking list length, etc. Based on the remaining length of the list
I would then print X across. Yah? Is their and easier approach I
might be overlooking?
For example...
mylist = ['serverA', 'serverB', 'serverC', 'serverD',' serverE',
'serverF', 'serverG']
Desired Output
============
serverA serverB serverC
serverD serverE serverF
serverG
I amend my prior solution to add a constant for the # of columns
COLS = 3
print '\n'.join(' '.join(mylist[i:i+COLS]) for i in
range(0,len(mylist),COLS))
--
Bob Gailer
919-636-4239
Chapel Hill NC
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