On 28/10/2012 21:37, Sandra Beleza wrote:
Hi, I have to write a script that asks the user for names one at a time, and accept the name only if the user did not gave it before. The script has to do this until it gets 3 unique names.So far I have this: def GetNames(): names=[] while len(names)<3: name=raw_input("Name: ") if name in names: print name, "is already in the data. Try again." if name not in names: names.append(name) names.sort() for each in names: print "Hurray for", each +"!" print However I cannot use the len() built in function. The Teacher is asking for another solution that does not use the len() t I know I can do it using the command: def Ask def GetNames(how_many): names=[] for el in range(how_many): name=raw_input("Name: ") if name in names: print name, "is already in the data. Try again." if name not in names: names.append(name) names.sort() for each in names: print "Hurray for", each +"!", print I cannot get 3 names, and it is easy to understand why (because the loop only iterates 3 times). But I don't know how to ask the user for names one at a time and to obtain 3 names and an output that looks like this: Name #1: Lewis Name #2: John Name #3: John John is already in the data. Try again. Name #3: Name #3: Chris Hurray for Chris! Hurray for John! Hurray for Lewis! Many Thanks!
In your original getNames do something like this. Initialise a counter to zero. Every time you get a valid name increment the count. If the count is three you're finished. -- Cheers. Mark Lawrence. _______________________________________________ Tutor maillist - Tutor@python.org To unsubscribe or change subscription options: http://mail.python.org/mailman/listinfo/tutor
