On 28/10/12 21:37, Sandra Beleza wrote:
def GetNames():
names=[]
while len(names)<3:
name=raw_input("Name: ")
if name in names:
print name, "is already in the data. Try again."
if name not in names:
names.append(name)
names.sort()
You should probably stop your function here by returning names.
for each in names:
print "Hurray for", each +"!"
print
It's good practice to keep the presentation logic outside
the function. Your loop would then change to
for each in getNames():
...
However I cannot use the len() built in function. The Teacher is asking
for another solution that does not use the len() t
That's bizarre. It forces you to write a bad solution.
However, Mark has already given you the necessary hint.
But using len() is absolutely the sane way to do this
(unless you are paranoid about micro performance).
--
Alan G
Author of the Learn to Program web site
http://www.alan-g.me.uk/
_______________________________________________
Tutor maillist - [email protected]
To unsubscribe or change subscription options:
http://mail.python.org/mailman/listinfo/tutor
