On Fri, Mar 29, 2013 at 9:39 PM, Amit Saha <amitsaha...@gmail.com> wrote:
> On Fri, Mar 29, 2013 at 9:35 PM, Amit Saha <amitsaha...@gmail.com> wrote:
>> On Fri, Mar 29, 2013 at 9:33 PM, Ghadir Ghasemi
>> <ghasemm...@leedslearning.net> wrote:
>>> Hi guys I am trying to create part of a vending machine. The section below
>>> is if the user wants to insert 50p coins. It works but when I entered a non
>>> integer like 'dfsdf', the program just broke. Is there a way that the
>>> program can check if the input is an integer, and if it is, then the
>>> program does all the calculations, but if it isn't the program just keeps
>>> asking for an input? Thanks. Here is the section.
>>>
>>> fiftypencecoins = int(input("how many 50p coins do you want to insert or
>>> press 'e' to exit : "))
>>> if fiftypencecoins == 'e':
>>> break
>>> else:
>>> currentmoney += fiftypencecoins * 5/10
>>> print("your newly updated credit is £" + str(currentmoney) + "0")
>>
>> Is this Python 3 or Python 2 ?
>
> May be that's not relevant. So anyway, if you want to see whether the
> int() function will be successful on your input, you need to check
> whether the input constitutes of only digits.
>
> I can think of two ways:
>
> 1. Easy and naive way: for each character in the input, check whether
> it is between [0-1]
Oh lord. That should be [0-9].
Sorry.
--
http://amitsaha.github.com/
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