On 29/03/2013 11:39, Amit Saha wrote:
On Fri, Mar 29, 2013 at 9:35 PM, Amit Saha <amitsaha...@gmail.com> wrote:
On Fri, Mar 29, 2013 at 9:33 PM, Ghadir Ghasemi
<ghasemm...@leedslearning.net> wrote:
Hi guys I am trying to create part of a vending machine. The section below is
if the user wants to insert 50p coins. It works but when I entered a non
integer like 'dfsdf', the program just broke. Is there a way that the program
can check if the input is an integer, and if it is, then the program does all
the calculations, but if it isn't the program just keeps asking for an input?
Thanks. Here is the section.
fiftypencecoins = int(input("how many 50p coins do you want to insert or press 'e'
to exit : "))
if fiftypencecoins == 'e':
break
else:
currentmoney += fiftypencecoins * 5/10
print("your newly updated credit is £" + str(currentmoney) + "0")
Is this Python 3 or Python 2 ?
May be that's not relevant. So anyway, if you want to see whether the
int() function will be successful on your input, you need to check
whether the input constitutes of only digits.
I can think of two ways:
1. Easy and naive way: for each character in the input, check whether
it is between [0-1]
2. Use regular expressions: http://docs.python.org/2/library/re.html
-Amit.
or;
where x is the input == fiftypencecoins;
return isinstance(x, int)
will return True or False
Then you can proceed as you wish.
--
Professor Sydney Shall,
Department of Haematological Medicine,
King's College London,
Medical School,
123 Coldharbour Lane,
LONDON SE5 9NU,
Tel & Fax: +44 (0)207 848 5902,
E-Mail: sydney.shall,
[correspondents outside the College should add; @kcl.ac.uk]
www.kcl.ac.uk
_______________________________________________
Tutor maillist - Tutor@python.org
To unsubscribe or change subscription options:
http://mail.python.org/mailman/listinfo/tutor
