Excuse me for the bad english: not "a random float numbers" but "random float numbers"
Gabriele 2014-02-17 11:13 GMT-05:00 Gabriele Brambilla < gb.gabrielebrambi...@gmail.com>: > No sorry, > > it's because my problem is not so simple: > imagine that in a100 contains not integer sorted in a good way but a > random float numbers. > How could I display only one item every 10? > > thanks > > Gabriele > > > 2014-02-17 11:08 GMT-05:00 Oscar Benjamin <oscar.j.benja...@gmail.com>: > > On 17 February 2014 16:05, Gabriele Brambilla >> <gb.gabrielebrambi...@gmail.com> wrote: >> > Hi, >> > >> > I'm wondering how I can (if I can) make a for loop in which I don't use >> all >> > the elements. >> > >> > for example >> > >> > a100 = list(range(100)) >> > >> > for a in a100: >> > print(a) >> > >> > it print out to me all the numbers from 0 to 99 >> > But if I want to display only the numbers 0, 9, 19, 29, 39, ...(one >> every 10 >> > elements) how can I do it WITHOUT defining a new list (my real case is >> not >> > so simple) and WITHOUT building a list of indexes? >> >> for a in a100: >> if a % 10 == 9: >> print(a) >> >> Alternatively: >> >> for a in a100: >> if a % 10 == 9: >> continue >> print(a) >> >> >> Oscar >> > >
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