Is there a function that can return the full path name when provided
with something along the lines of
"../../myfile"?
Just to be able to glean the current working directory would suffice. (I
could use a shell command if I had to but was hoping it could be done
all within Python.
(python 2.7 on Ubuntu 12.4)
I've searched the os.path and glob modules to no avail.
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