On 04/01/2015 11:04 AM, Alan Gauld wrote:
On 01/04/15 05:50, Jim Mooney wrote:
s = [1,2,3,4,5,6,7,8]
list(zip(*[iter(s)]*2))
[(1, 2), (3, 4), (5, 6), (7, 8)]
Personally I'd have used slicing in this example:
zip(s[::2],s[1::2])
With an emphasis on *in this example*.
The idiom you are citing works on any iterable, not all of which support
slicing and the slicing version requires two passes over the data.
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