On 01/04/2015 18:20, Roel Schroeven wrote:
Mark Lawrence schreef:
On 01/04/2015 11:50, Alan Gauld wrote:
On 01/04/15 11:04, Wolfgang Maier wrote:
On 04/01/2015 11:04 AM, Alan Gauld wrote:
On 01/04/15 05:50, Jim Mooney wrote:
s = [1,2,3,4,5,6,7,8]
list(zip(*[iter(s)]*2))
[(1, 2), (3, 4), (5, 6), (7, 8)]
Personally I'd have used slicing in this example:
zip(s[::2],s[1::2])
With an emphasis on *in this example*.
The idiom you are citing works on any iterable, not all of which
support
slicing and the slicing version requires two passes over the data.
Agreed, but readability always trumps performance,
unless performance is critical.
In which case readability usually trumps performance.
And especially on a beginners list.
In which case I'll stick with the more-itertools pairwise() function
Which does not the same thing. Original:
>>>>>>>> s = [1,2,3,4,5,6,7,8]
>>>>>>>> list(zip(*[iter(s)]*2))
>>>>>>>> [(1, 2), (3, 4), (5, 6), (7, 8)]
Pairwise:
>>> take(4, pairwise(count()))
[(0, 1), (1, 2), (2, 3), (3, 4)]
Greetings,
Roel
Yo are of course completely correct, I was conflating two different
threads :)
--
My fellow Pythonistas, ask not what our language can do for you, ask
what you can do for our language.
Mark Lawrence
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